51单片机 跑马灯程序

2025-04-18 12:53:26
推荐回答(4个)
回答1:

org 0000h

    jmp start

    org 0030h

start:

    mov p0,#11111110b  ;  此时第一个灯亮

    call t10s

    mov p0,#11111101b  ;此时第二个灯亮

    call t10s

    mov p0,#11111011b

    call t10s

    mov p0,#11110111b

    call t10s

    mov p0,#11101111b

    call t10s

    mov p0,#11011111b

    call t10s

    jmp start        ;此处跳到开始 即 循环

;延时子程序10秒=250usX2X200X100

t10s:mov r5,#100

lpr5:mov r6,#200

lpr6:mov r7,#250

    djnz r7,$

    djnz r6,lpr6

    djnz r5,lpr5

  ret

  end

把灯的正极接电源正极 即vcc 负极分别接p0.0-p0.5

此时  给p0  送0灯就亮 1灯就不亮

程序已经过调试 可用

仿真如下:

回答2:

用汇编语言实现的程序如下。
本程序已经经过在Proteus上验证、仿真成功。

ORG 0000H
SJMP _START
ORG 0050H
_START:
MOV P1, #0xFE
CALL DL10S
MOV P1, #0xFD
CALL DL10S
MOV P1, #0xFB
CALL DL10S
MOV P1, #0xF7
CALL DL10S
MOV P1, #0xEF
CALL DL10S
MOV P1, #0xDF
CALL DL10S
SJMP _START

DL10S:
MOV R5, #100
_DELAY100MS:
MOV R6, #200 ;1T
DL250T:
MOV R7, #250 ;1T
D2:
DJNZ R7, D2 ;2T, 原地转移250遍, 共用500T
DJNZ R6, DL250T ;2T, 转移200遍
DJNZ R5, _DELAY100MS
RET ;2T
END

回答3:

#include

void main()
{
unsigned char ch[10]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};/*0--9*/
unsigned char i,j;
j=1;
P2=P2&0x00;
P1=0xef;
P0=0xa4;
while(1)
{
i=P1;
i=i;
if(i==0xee)
{
P0=0xb0;

}
}

}

回答4:

c还是汇编呀?

#include

void delay(void);
void main()
{
do{
P1=0xFE;
delay();
P1=0xFD;
delay();
P1=0xFB;
delay();
P1=0xF7;
delay();
P1=0xEF;
delay();
P1=0xDF;
delay();
P1=0xBF;
delay();
P1=0x7F;
delay();
}while(1);
}

void delay()
{
unsigned int x=60000;
do{ x--;
}while(x>1);
}