用初等变换化成对角矩阵 (1 2 3 4 0 -1 0 -2 1 1 3 2 2 2 6 4)

(1 2 3 4 0 -1 0 -2 1 1 3 2 2 2 6 4)为4*4矩阵
2025-04-13 23:13:24
推荐回答(1个)
回答1:

A=
[1 1 2 1]
[2 -1 2 4]
[1 -2 0 3]
[4 1 4 2]
行初等变换为
[1 1 2 1]
[0 -3 -2 2]
[0 -3 -2 2]
[0 -3 -4 -2]
行初等变换为
[1 1 2 1]
[0 3 2 -2]
[0 0 -2 -4]
[0 0 0 0]
行初等变换为
[1 1 0 -3]
[0 3 0 -6]
[0 0 1 2]
[0 0 0 0]
行初等变换为
[1 0 0 -1]
[0 1 0 -2]
[0 0 1 2]
[0 0 0 0]