arctan(1⼀1-x)左右极限怎么求? x=1或者-1时

arctan(1/1-x)左右极限怎么求?x=1或者-1时
2025-04-08 08:21:36
推荐回答(1个)
回答1:

看符号
arctan(正无穷大)=二分之派
arctan(负无穷大)=负二分之派
x->1+ arctan(1/(1-x))=arctan(负无穷大)=负二分之派
x->1- arctan(1/(1-x))=arctan(正无穷大)=二分之派

x->-1 arctan(1/(1-x))=arctan(1/2)