标准状态(p1=101325Pa,T1=273.15K)下,1molCO2的体积=22.4L,质量44g,密度rou1=1.964g/L由理想气体状态方程pV=nRTpV=m/MRTpM=rou*RT rou是密度那么p2=1.2MP,T2=303.15K时,密度rou2=p2T1/(p1T2) * rou1= 20.96 g/L
