根号下大于等于0所以log(1/2)(3x-2)>=0底数满足0<1/2<1所以log(1/2)(x)是减函数且0=log(1/2)(1)所以3x-2<=1x<=1真数大于03x-2>0x>2/3所以定义域(2/3,1]
定义域:真数3x-2>0,得x>2/3根号下大于等于零,则log1/2 (3x-2)>=0所以有:0<3x-2<=1即2/3即定义域是(2/3,1]
