每对折一次,厚度乘以2,故对折n次后的厚度为d = 2^n (mm) = 2^n×10^(-3) m要达到珠穆朗玛峰的高度,有d = 2^n ×10^(-3) ≥ 8848.13得n ≥ log_(2)(8848130) ≈ 23.077∴ n ≥ 24 ,即至少对折24次.
