(3+2√2-√3-√6)/(1+√2-√3). =[(1+√2-√3)+(2+√2-√6)/(1+√2-√3). =[(1+√2-√3)+√2(1+√2-√3)/(1+√2-√3). =(1+√2)(1+√2-√3)/(1+√2-√3) =1+√2
