(1)Ka(HAc) =1.8*10^-5(2)求加入NaAc前,溶液的pH值和HAc的解离度?[H+] = (Kac)^1/2 =(1.8*10^-5 *0.1)^1/2=1.34*10^-3 mol/LPH =2.87(3)加入NaAc前HAc的解离度= 1.34*10^-3/0.1 *100% =1.34%(4)加入固体NaAc ?