(1)计算:[x(x2y2-xy)-y(x2-x3y)]?x2y;(2)先化简,再求值:(x+2)2+(2x+1)(2x-1)-4x(x+1

2025-04-05 14:49:52
推荐回答(1个)
回答1:

(1)原式=[x3y2-x2y-x2y+x3y2]?x2y
=[2x3y2-2x2y]?x2y
=2x5y3-x4y2
(2)原式=x2+4x+4-4x2-1-4x-4x2
=x2+3,
当x=

1
2
时,
原式=
13
4