tan∝=2-√3时,tan(∝+π⼀4)的值为啥是根号3,怎么算的?

2025-04-08 05:27:49
推荐回答(1个)
回答1:

tan(α+π/4)
=(tanα+tanπ/4)/(1-tanα tanπ/4)
=(1+2-√3)/(1-2+√3)
=(3-√3)/( √3-1)
=√3 (√3-1) /(√3-1)
=√3