y=x^2, y=0, x=1x=1, =>y =1y=0 => x=0Vy =π∫(0->1) (√y) ^2 dy=(1/2)π[y^2]|(0->1)=(1/2)πVx=π∫(0->1) (x^2) ^2 dx=(1/5)π[x^5]|(0->1)=(1/5)π
