解方程:(1)4x2-8x-5=0(用配方法) (2)4x2...

2025-04-09 09:45:39
推荐回答(1个)
回答1:

(1)4x2-8x-5=0(用配方法)
移项得:4x2-8x=5,
则x2-2x=

5
4

x2-2x+1=
5
4
+1,
(x-1) 2=
9
4

x-1=±
3
2

x1=
5
2
;x2=-
1
2


(2)4x2-25=0(用因式分解法)
(2x+5)(2x-5)=0,
解得:x1=-2.5;x2=2.5;

(3)4(x-2)2-120=1
4(x-2)2-121=0,
[2(x-2)+11)][2(x-2)-11]=0,
解得:x1=-3.5;x2=7.5;

(4)x2+x-6=0
(x-2)(x+3)=0,
解得:x1=2;x2=-3.