延长AE交BC延长线于点G则△ADE全等于△GCE∴AD=CG ∠DAE=∠G∵∠DAE=∠EAF∴∠EAF=∠G∴AF=FG设FC=X BC=aa²+(a-x)²=(x+a)²x=a/4∴CF=BC/4