设本月人均工作量为x
(1)(4x+20)/4=(6x-20)/5
x+5=6/5x-4
-1/5x=-9
x=45
(2)(4x+20)/4=(6x-20)/5+2
x+5=6/5x-4+2
-1/5x=-7
x=35
(3))(4x+20)/4=(6x-20)/5-2
x+5=6/5x-4-2
-1/5x=-11
x=55
题是什么,我帮你解答 。设本月人均工作量为x
(1)(4x+20)/4=(6x-20)/5
x+5=6/5x-4
-1/5x=-9
x=45
(2)(4x+20)/4=(6x-20)/5+2
x+5=6/5x-4+2
-1/5x=-7
x=35
(3))(4x+20)/4=(6x-20)/5-2
x+5=6/5x-4-2
-1/5x=-11
x=55
设此月人均定额是x件
(1)(4x+20)/4=(6x-20)/5
x+5=6/5x-4
-1/5x=-9
x=45
(2)(4x+20)/4=(6x-20)/5+2
x+5=6/5x-4+2
-1/5x=-7
x=35
(3))(4x+20)/4=(6x-20)/5-2
x+5=6/5x-4-2
-1/5x=-11
x=55
7、(1)设此月人均定额是x件
(4x+20)/4=(6x-20)/5
x=45
(2)设此月人均定额是x件
(4x+20)/4=(6x-20)/5+2
x=35
(3)设此月人均定额是x件
(4x+20)/4=(6x-20)/5-2
x=55
解:设次月人均定额为X件
(1)1/4(4x+20)=1/5(6x-20) x=45
(2) 1/4(4x+20)=1/5(6x-20)+2 x=35
(3)1/4(4x+20)=1/5(6x-20)-2 x=55