C语言 输入表格中的某公司销售员工的工资信息,

录入结构，生成链表。
功能简单，我都写在main函数中，如果你写项目，建议按功能拆成多个函数调用。

#include 
#include 
typedef struct persl
{
    int id;
    char name[20];
    int age;
    float bpay;
    float x;
    float acmt;
    struct persl *next;
}PERSL;
int main()
{
    int ages=0,cnt=0;
    float pays=0,pay=0;
    char c;
    PERSL *perslTail=NULL,*perslNew=NULL,*perslHead=(PERSL *)malloc(sizeof(PERSL));
    perslHead->next=NULL;
    printf("录入员工信息\n");
    while(1)//---------录入
    {
        perslNew=(PERSL *)malloc(sizeof(PERSL));
        perslNew->next=NULL;
        printf("编号:");
        scanf("%d",&perslNew->id);
        printf("姓名:");
        scanf("%s",perslNew->name);
        printf("年龄:");
        scanf("%d",&perslNew->age);
        printf("基本工资:");
        scanf("%f",&perslNew->bpay);
        printf("系数:");
        scanf("%f",&perslNew->x);
        printf("业绩:");
        scanf("%f",&perslNew->acmt);
        if(!perslHead->next)
            perslHead->next=perslNew;
        else
            perslTail->next=perslNew;
        perslTail=perslNew;
        printf("是否继续录入？Y/N\n");
        getchar();
        scanf("%c",&c);
        if(c=='N')
            break;
    }
    printf("编号   姓名   年龄  基本工资  系数  业绩)：\n");
    while(perslHead->next)//----------打印
    {
        cnt++;
        ages+=perslHead->next->age;
        pay=perslHead->next->bpay+perslHead->next->acmt*0.01*perslHead->next->x;
        pays+=pay;
        printf("%03d  %s  %d   %f\n",perslHead->next->id,perslHead->next->name,perslHead->next->age,pay);
        perslHead=perslHead->next;
    }
    printf("平均年龄及平均工资：%d，%f\n",ages/cnt,pays/cnt);
    return 0;
}