已知sina=-4⼀5,a∈(π,3π⼀2),cosb=-12⼀13,b∈(π⼀2,π)

求1.sin(a+b) 2.cos2a
2025-04-10 00:35:48
推荐回答(2个)
回答1:

sina=-4/5,a∈(π,3π/2)
cosa=-3/5
cosb=-12/13,b∈(π/2,π)
sinb=5/13

sin(a+b)
=sinacosb+cosasinb
=-4/5*(-12/13)+(-3/5)*5/13
=48/65-15/65
=33/65

cos2a
=1-2sin²a
=1-2*(-4/5)²
=1-32/25
=-725

回答2:

1.∵sina=-4/5 a∈(π,3π/2)
∴cosa=-3/5
∵cosb=-12/13,b∈(π/2,π)
∴sinb=5/13
∴sin(a+b)=sinacosb+sinbcosa=48/65-15/65=33/65
2.∵cos2a=cos^(2)a-sin^(2)a=9/25-16/25=-7/25