由图可知,A=3,
T=1 4
?7π 12
=π 3
,π 4
∴T=π,则ω=
=2π T
=2.2π π
由五点作图的第四点可知,2×
+φ=π 3
,得φ=3π 2
.5π 6
∴f(x)=3sin(2x+
).5π 6
由f(α)=1,得3sin(2α+
)=1.5π 6
sin(2α+
)=5π 6
.1 3
∵α∈(0,
),π 3
∴2α+
∈(5π 6
,5π 6
).3π 2
cos(2α+
)=?5π 6
=-
1?(
)2
1 3
.2
2
3
∴sin2α=sin(2α+
?5π 6
)5π 6
=sin(2α+
)cos5π 6
?cos(2α+5π 6
)sin5π 6
5π 6
=
×(?1 3