|3k-4|/√(k^2+1^2)=√10 => |3k-4|=√[10(k^2+1)] => 9k^2-24k+16=10k^2+10 => k^2+24k-6=0 => k=-12±[√(24*25)]/2=-12±5√6 ∴ k1=-12+5√6、 k2=-12-5√6
