解下列方程:{5⼀x+1+4⼀y-2=2,7⼀x+1+3⼀2-y=13⼀20

2025-04-06 04:33:45
推荐回答(1个)
回答1:

5/(x+1)+4/(y-2)=2
7/(x+1)+3/(2-y)=13/20
7/(x+1)-3/(y-2)=13/20
令a=1/(x+1),b=1/(y-2)
5a+4b=2 (1)
7a-3b=13/20 (2)
(1)*3+(2)*4
15a+28a=6+13/5=8.6
43a=8.6
a=1/5
b=(2-5a)/4=1/4
所以x+1=1/a=5
y-2=1/b=4
x=4
y=6