已知A=-2^5,B=2^5,求A^2-2A*B+B^2和A^3-3A^2*B+3A*B^2-B^3

(2)若2m+4n-3=0,试求4^m*16^n的值
2025-04-07 07:06:10
推荐回答(1个)
回答1:

A^2-2A*B+B^2
=(A-B)^2
=(-2^5-2^5)^2
=2^12
A^3-3A^2*B+3A*B^2-B^3
=(A-B)^3
=(-2^5-2^5)^3
=-2^18
2m+4n-3=0
2m+4n=3
4^m*16^n
=2^2m*2^4n
=2^(2m+4n)
=2^3
=8