你好！原式=4i（√3+i）/4 =-1+√3i =2(-1/2+√3/2) = 2[cos(2π/3)+isin(2π/2)]如有不懂请追问满意请采纳有其他问题，请采纳本题后点追问答题不易，望合作O(∩_∩)O~祝学习进步
