1)
=((2√5+5√2-(2√5-5√2))((2√5+5√2)+(2√5-5√2))
=10√2*4√5=40√10
2)a+c=32,a-b=2√2-3,b+c=35-2√2
原式=3-2√2+4√2+35-2√2=38
(1)
(2√5+5√2)^2-(2√5-5√2)^2
=[(2√5+5√2)+(2√5-5√2)][(2√5+5√2)-(2√5-5√2)]
=4√5*10√2
=40√10
(2)
a+3=b+2√2=35-c
a-b=2√2-3
a+c=35-3=32
b+b=35-2√2
/a-b/+(√a+c)+b+c
=3-2√2+√32+35-2√2
=3-2√2+5√2+35-2√2
=38+√2
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