泰勒公式 f(x)=f(a)+f'(a)(x-a)/1!+f²(a)(x-a)²/2!+…+［f^n(a)］(x-a)^n/n!+Rn(x) f(x)=sin2x, a=π/2 f'(x)=2cos2x=2^1sin(2x+1×π/2), f"(x)=-4sin2x=2^2sin(2x+2×π/2), … , f^n(x)=2 ^n · sin(2x+nπ/2) 所以 f(a)=0, f'(a)=-2, f"(a)...
